(2x+1)(x-5)=2x^2-2

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Solution for (2x+1)(x-5)=2x^2-2 equation:


Simplifying
(2x + 1)(x + -5) = 2x2 + -2

Reorder the terms:
(1 + 2x)(x + -5) = 2x2 + -2

Reorder the terms:
(1 + 2x)(-5 + x) = 2x2 + -2

Multiply (1 + 2x) * (-5 + x)
(1(-5 + x) + 2x * (-5 + x)) = 2x2 + -2
((-5 * 1 + x * 1) + 2x * (-5 + x)) = 2x2 + -2
((-5 + 1x) + 2x * (-5 + x)) = 2x2 + -2
(-5 + 1x + (-5 * 2x + x * 2x)) = 2x2 + -2
(-5 + 1x + (-10x + 2x2)) = 2x2 + -2

Combine like terms: 1x + -10x = -9x
(-5 + -9x + 2x2) = 2x2 + -2

Reorder the terms:
-5 + -9x + 2x2 = -2 + 2x2

Add '-2x2' to each side of the equation.
-5 + -9x + 2x2 + -2x2 = -2 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-5 + -9x + 0 = -2 + 2x2 + -2x2
-5 + -9x = -2 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-5 + -9x = -2 + 0
-5 + -9x = -2

Solving
-5 + -9x = -2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -9x = -2 + 5

Combine like terms: -5 + 5 = 0
0 + -9x = -2 + 5
-9x = -2 + 5

Combine like terms: -2 + 5 = 3
-9x = 3

Divide each side by '-9'.
x = -0.3333333333

Simplifying
x = -0.3333333333

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